第一級陸上無線技術士試験 無線工学B 数学

\[ \begin{eqnarray} \log_{10} 2&=&0.3 \\ \log_{10} 3&=&0.477 \\ \log_{10} 5&=&0.7 \end{eqnarray} \]

\[ \begin{array}{|c|c|c|c|}\hline \theta&\frac16\pi\left(=30^\circ\right)&\frac14\pi\left(=45^\circ\right)&\frac13\pi\left(=60^\circ\right) \\ \hline \sin\theta&\frac12\left(=\frac{\sqrt1}2\right)&\frac1{\sqrt 2}\left(=\frac{\sqrt2}2\right)&\frac{\sqrt3}2 \\ \hline \cos\theta&\frac{\sqrt3}2&\frac1{\sqrt2}\left(=\frac{\sqrt2}2\right)&\frac12\left(=\frac{\sqrt1}2\right) \\ \hline \tan\theta\left(=\frac{\sin\theta}{\cos\theta}\right)&\frac1{\sqrt3}&1&\sqrt3 \\ \hline \end{array} \]

\[ \cfrac d {dx}e^{ax}=ae^{ax} \]

\[ \cfrac d {d\theta} \sin a\theta=a \cos a\theta \]

\[ \int \cos a\theta d\theta=\cfrac 1 a \sin a\theta \]

\[ (1+x)^n=1+nx \]

\[ j^2=-1 \]

\[ \begin{eqnarray} |1+j|&=&\sqrt{1^2+1^2}&=&\sqrt2 \\ |1-j|&=&\sqrt{1^2+(-1)^2}&=&\sqrt2 \end{eqnarray} \]

\[ \begin{eqnarray} \frac 1{\pi}&\fallingdotseq&0.318 \\ \frac {2\sqrt3}{\pi}&\fallingdotseq&2\sqrt3\times0.318=1.1 \end{eqnarray} \]